Asked by Kat
A 34.6 g block of metal at 2.1oC is dropped into 100.0 g of water at 97.3oC. If the specific heat of the metal is 0.084 cal/goC, what will the final temperature of the water be?
Answers
Answered by
DrBob222
heat gained by metal + heat lost by water = 0
[mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass water x specific heat water x (Tfinal-Tnitial) = 0
Solve for Tfinal.
[mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass water x specific heat water x (Tfinal-Tnitial) = 0
Solve for Tfinal.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.