Question
A 34.6 g block of metal at 2.1oC is dropped into 100.0 g of water at 97.3oC. If the specific heat of the metal is 0.084 cal/goC, what will the final temperature of the water be?
Answers
DrBob222
heat gained by metal + heat lost by water = 0
[mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass water x specific heat water x (Tfinal-Tnitial) = 0
Solve for Tfinal.
[mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass water x specific heat water x (Tfinal-Tnitial) = 0
Solve for Tfinal.