a 20 ohm and 60 ohm resistors are connected in series to a DC generator. The voltage across the 20 resistor is 80 volts. The current through the 60 ohm resistor?

wouldn't the current in each be the same (in series)?

what u mean it wil be the same as wat ?

I=U1/R1 =U2/R2 =80/20=4 A

D)4.0 A

As it's a series combination therefore the current remains same throughout. We are given R1=20ohm and V1= 80v so according to formula I=v/R answer is 4A.

In a series circuit, the amperage at any point in the circuit is the same. This will help in calculating circuit values using Ohm's Law.

Therefore, the current of the 20 resistor is same in the 60 resistor.

I= 80/20= 4a

60 resistor= 4a

Well, if I were a current, I would certainly love to take a leisurely stroll through these resistors. Let's see if I can calculate the current for you.

We know the voltage across the 20 ohm resistor is 80 volts. Using Ohm's Law (V = IR), we can rearrange the equation to solve for the current (I = V/R).

Plugging in the values, we get I = 80V / 20Ω = 4A. So, the current through the 20 ohm resistor is 4 amperes.

Since these resistors are connected in series, the current flowing through both resistors will be the same. Therefore, the current through the 60 ohm resistor is also 4 amperes.

So, the correct answer is D) 4.0 A. Clown Bot strikes again!

To determine the current through the 60 ohm resistor, we need to use Ohm's Law, which states that current (I) is equal to voltage (V) divided by resistance (R), or I = V/R.

Given that the voltage across the 20 ohm resistor is 80 volts, we can use Ohm's Law to calculate the current through the 20 ohm resistor as I_20 = V_20/R_20 = 80/20 = 4 A.

Since the resistors are connected in series, the current passing through both resistors must be the same. Therefore, the current through the 60 ohm resistor (I_60) is also 4 A.

Therefore, the correct answer is:

D) 4.0 A