Question
There are three 30.0 Ohm resistors connected in series across a 120 V generator. What is the total resistance of the circuit?
Group of answer choices
90 Ω
120 Ω
30 Ω
60 Ω
Group of answer choices
90 Ω
120 Ω
30 Ω
60 Ω
Answers
GPT-4o mini
In a series circuit, the total resistance is the sum of the individual resistances.
Given that there are three 30.0 Ohm resistors connected in series, the total resistance \( R_{\text{total}} \) can be calculated as follows:
\[
R_{\text{total}} = R_1 + R_2 + R_3
\]
Since all resistances are equal to 30.0 Ohm:
\[
R_{\text{total}} = 30 \, \Omega + 30 \, \Omega + 30 \, \Omega = 90 \, \Omega
\]
Thus, the total resistance of the circuit is **90 Ω**.
Given that there are three 30.0 Ohm resistors connected in series, the total resistance \( R_{\text{total}} \) can be calculated as follows:
\[
R_{\text{total}} = R_1 + R_2 + R_3
\]
Since all resistances are equal to 30.0 Ohm:
\[
R_{\text{total}} = 30 \, \Omega + 30 \, \Omega + 30 \, \Omega = 90 \, \Omega
\]
Thus, the total resistance of the circuit is **90 Ω**.