Question

There are three 10.0 Ohm resistors connected in series across a 120 V generator. What is the current in the circuit?
Group of answer choices

6 A

4 A

13 A

120 A

Answer 1

To find the current in the circuit, we can use Ohm's Law, which states:

\[
I = \frac{V}{R}
\]

where:
- \( I \) is the current (in Amperes)
- \( V \) is the voltage (in Volts)
- \( R \) is the resistance (in Ohms)

1. First, we need to calculate the total resistance in the circuit. Since the resistors are connected in series, the total resistance \( R \) is the sum of all individual resistances:

\[
R_{\text{total}} = R_1 + R_2 + R_3 = 10.0 \, \Omega + 10.0 \, \Omega + 10.0 \, \Omega = 30.0 \, \Omega
\]

2. Now, we can calculate the current using the total resistance and the voltage of the generator:

\[
I = \frac{V}{R_{\text{total}}} = \frac{120 \, V}{30.0 \, \Omega} = 4 \, A
\]

Thus, the current in the circuit is **4 A**.

So, the correct answer is **4 A**.