To find the current in the circuit, we can use Ohm's Law, which states:
\[ I = \frac{V}{R} \]
where:
- \( I \) is the current (in Amperes)
- \( V \) is the voltage (in Volts)
- \( R \) is the resistance (in Ohms)
- First, we need to calculate the total resistance in the circuit. Since the resistors are connected in series, the total resistance \( R \) is the sum of all individual resistances:
\[ R_{\text{total}} = R_1 + R_2 + R_3 = 10.0 , \Omega + 10.0 , \Omega + 10.0 , \Omega = 30.0 , \Omega \]
- Now, we can calculate the current using the total resistance and the voltage of the generator:
\[ I = \frac{V}{R_{\text{total}}} = \frac{120 , V}{30.0 , \Omega} = 4 , A \]
Thus, the current in the circuit is 4 A.
So, the correct answer is 4 A.