Asked by Darrell
An engine expends 44.0 hp in moving a car along a level track at a speed of 13.9 m/s. How large is the total force acting on the car in the opposite direction of the motion of the car?
Answers
Answered by
drwls
44.0 hp = 32,824 Joules/s, since there are 746 watts per Hp.
That equals the friction force x velocity
Therefore friction force = 32,824/13.9 = 2362 N
That equals the friction force x velocity
Therefore friction force = 32,824/13.9 = 2362 N
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