Asked by Leah
A robot arm expends 15J of work to extend a spring 10cm from its equilibrium position. How much force is required?
Answers
Answered by
bobpursley
energy=1/2 k x^2
15=1/2 k (.1)^2 solve for k.
Force= k *.1
15=1/2 k (.1)^2 solve for k.
Force= k *.1
Answered by
Anonymous
15
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