Asked by Duane
A student expends 9.6W of power lifting a textbook 0.50m in 3.0s with a constant velocity. How much work is done?
Answers
Answered by
Steve
just watch the units:
9.6 J/s * 3.0s = 28.8 J
The height lifted is irrelevant, since that will just be part of the work.
9.6 J/s * 3.0s = 28.8 J
The height lifted is irrelevant, since that will just be part of the work.
Answered by
Antonio Greenlee
9.6 J/s * 3.0s = 28.8 J
The height lifted is irrelevant, since that will just be part of the work.
The height lifted is irrelevant, since that will just be part of the work.
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