Asked by Marysvoice
Building a rectangular room with fixed perimeter of 280ft
what dimentions would yield the maximum area?
What dimentions would yeild the minimum area?
what dimentions would yield the maximum area?
What dimentions would yeild the minimum area?
Answers
Answered by
Reiny
A rectangle of largest area is a square.
So divide your perimeter by 4.
To build a room of minimum area is a rather silly question.
So divide your perimeter by 4.
To build a room of minimum area is a rather silly question.
Answered by
Damon
x = length
y = width
A = x y
x+y=140
A = x(140-x)
A = 140 x - x^2
look at shape of parabola by completing the square
x^2 -140 x = -A
x^2 - 140 x + 4900 = -A + 4900
(x-70)^2 = -A + 4900
the vertex will be at x = 70 and A = 4900 and the -A means that the parabola opens down (sheds water) so that vertex is the maximum where x = y =70 as Reiny told you.
since a negative x or y does not make much sense, the area may not get any smaller than zero when x --> 0 or y -->0 0
y = width
A = x y
x+y=140
A = x(140-x)
A = 140 x - x^2
look at shape of parabola by completing the square
x^2 -140 x = -A
x^2 - 140 x + 4900 = -A + 4900
(x-70)^2 = -A + 4900
the vertex will be at x = 70 and A = 4900 and the -A means that the parabola opens down (sheds water) so that vertex is the maximum where x = y =70 as Reiny told you.
since a negative x or y does not make much sense, the area may not get any smaller than zero when x --> 0 or y -->0 0
Answered by
Marysvoice
I apologize for my silly question. I followed your advice, revised my question and found my answer. Thank you.
Answered by
Shainah
Wasn't very helpful.
Answered by
Omoso
Yes
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