Asked by Tolar
An alpha particle(the nucleus of a helium atom) has a mass of 6.64*10^-27kg and a charge of +2e. What are the magnitude and direction of the electric field that will balance the gravitational force on it? Mp= 1.67*10^-27kg
Answers
Answered by
Elena
qE =mg,
E = mg/q = 6.64•10^-27•9.8/2•1.6•10^-19 =2.03•10^-7 V/m
E = mg/q = 6.64•10^-27•9.8/2•1.6•10^-19 =2.03•10^-7 V/m
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