Asked by kerry
a square pyramid resting on its base is filled to half its height with 320 cm^3 water. how much water is needed to finish filling the pyramid?
Answers
Answered by
Steve
at half its height, all linear dimensions are also half their original values.
So, the base of the empty pyramid is 1/4 the base of the whole pyramid.
empty volume is thus (B/4)*(h/2) = Bh/8 = 40
So, the base of the empty pyramid is 1/4 the base of the whole pyramid.
empty volume is thus (B/4)*(h/2) = Bh/8 = 40
Answered by
Steve
I misread the problem. I was thinking the original volume was 320.
Instead, 320 is 7/8 of the original volume, so we still need 1/8 of the original volume to finish filling it. That is 1/7 of what was already used, or 320/7 = 45.7 cm^3
Instead, 320 is 7/8 of the original volume, so we still need 1/8 of the original volume to finish filling it. That is 1/7 of what was already used, or 320/7 = 45.7 cm^3
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