Asked by Anonymous
A right square pyramid has a surface area of 75.5m^2 and a base length of 3.5m. What is the slant height of this right pyramid?
Answers
Answered by
Reiny
Clearly the surface area would consist only of the 4 triangles.
area of one of them = 75.5/4 or 18.875 m^2
area = (1/2)base x height
18.875 = (1/2)(3.5)h
h = 2(18.875)/3.5 = appr 10.7857
clean up to whatever accuracy is expected
I would say 10.8 , since the original data had one decimal
area of one of them = 75.5/4 or 18.875 m^2
area = (1/2)base x height
18.875 = (1/2)(3.5)h
h = 2(18.875)/3.5 = appr 10.7857
clean up to whatever accuracy is expected
I would say 10.8 , since the original data had one decimal
Answered by
Anonymous
but the answer is 9.0 and 10.8 won't work for the other questions :(
Answered by
Reiny
define what you mean by slant height.
Answered by
Anonymous
the height that's not at the center but on the side?
Answered by
Reiny
then I am right
check:
area of one triangle = (1/2)(3.5)(10.7857
= 18.875
4 such triangle = 4(18.875) = 75.5
check:
area of one triangle = (1/2)(3.5)(10.7857
= 18.875
4 such triangle = 4(18.875) = 75.5
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