Δp = F•Δt,
Δp = p2 - p1 =m•v1 - m• (-v2) =
= m• (v1+v2),
F•Δt = m• (v1+v2),
F = m•(v1+v2)/ Δt = 0.06(40+36)/0.025=
= 182.4 N.
A .060kg tennis ball crosses the net a 40m/s and is returned back across the net at 36m/s by the other player. If the contact time between racket and the ball is .0250s, what is the average force on the ball?
1 answer