Asked by anonymous
A tennis ball (m= 0.2 kg) is thrown at a brick wall. It is traveling horizontally at 16 just before hitting the wall and rebounds from the wall at 8 , still traveling horizontally. The ball is in contact with the wall for 0.04 s. What is the magnitude of the average force of the wall on the ball?
Answers
Answered by
Henry
a = (V-Vo)/t = (-8-16)/0.04 = -600 m/s^2
F = m*a = 0.2 * (-600) = -120 N.
F = m*a = 0.2 * (-600) = -120 N.
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