The 0.060 kg tennis ball was traveling at 45 m/s (100 mph) and made a perfectly elastic collision with a wall and bounces back. If it is in contact with the wall for 0.15 s, what was the force the ball experienced from the wall?

asked by anon

4 years ago

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1 answer

acceleration = (45m/s)/(0.15s) = 300 m/s^2
F = ma

answered by oobleck

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Question

The 0.060 kg tennis ball was traveling at 45 m/s (100 mph) and made a perfectly elastic collision with a wall and bounces back. If it is in contact with the wall for 0.15 s, what was the force the ball experienced from the wall?

1 answer

acceleration = (45m/s)/(0.15s) = 300 m/s^2
F = ma

oobleck · Answer

acceleration = (45m/s)/(0.15s) = 300 m/s^2 F = ma