Asked by Amy
Find the vertex,axis,focus,directrix of y+1= -1/8(x-1)^2
Answers
Answered by
Reiny
just take the +1 to the other side to get
y = (-1/8) (x-1)^2 - 1
now you have it in standard form and you can get the information easily
y = (-1/8) (x-1)^2 - 1
now you have it in standard form and you can get the information easily
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