Ask a New Question

Asked by clarke

Find the vertex, focus, and directrix of the parabola.

x= 1/40 y^2
3 years ago

Answers

Answered by oobleck
recall that
y^2 = 4px has
vertex at (0,0)
focus at x = p
directrix at y = -p

so plug in your numbers
3 years ago
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions

Find the vertex, focus, axis, directrix and latus rectum of the parabola x^2+ y = 6x - 14 Find the vertex, focus, and axis of symmetry of the parabola x^2-10x-8y+29 = 0. ==> I do it over... Find the vertex, focus and directrix of the parabola. 4x - y^2 - 2y - 33 = 0 y^2+2y+1 = -4x+... Find the vertex, focus, and directrix of the parabola. x^2 - 2x + 8y + 9 = 0 x^2 - 2x +1 = -... Find the vertex, focus, and directrix of the parabola. x^2 - 2x + 8y + 9 = 0 x^2 - 2x +1 = -... Find the vertex and focus of the parabola. (x^2)-(24y) = 0 Find the vertex and focus of the parabola with the following equation: y = x2 + 6x + 5 Find the Vertex, Focus, and Directrix of the parabola: x^2 -12x-48y+276=0 Thank you so much <3 How do I find vertex, focus and directrix for the following functions? y^2−16y=12x−8^2 x^2+16x... Find the​ vertex, focus, and directrix of the parabola. xequals StartFraction 1 Over 28 EndFraction...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use