When the molecules react 1:1 as they do in this case you can use
mL acid x M acid = mL base x M base.
If 34.7 mL of 0.210 M KOH is required to completely neutralize 30.0 mL of a CH3COOH solution, what is the molarity of the acetic acid solution?
2 answers
what volume of 1.90 M SrCl2 is needed to prepare 525mL of 5.00mM SrCl2?