Asked by samantha
How many ml of a .25M HCL would be required to neutralize completely 2.5g of NaOH
Answers
Answered by
DrBob222
Write the equation and balance it.
NaOH + HCl ==> NaCl + H2O
mols NaOH = 2.5g/molar mass NaOH.
mols HCl required = mols NaOH (from the equation).
Then mol HCl = M(HCl) x L(HCl). You have the molarity of the HCl and you have the mols of HCl from your calculation, which leaves just one unknown (the L). Convert that to mL.
NaOH + HCl ==> NaCl + H2O
mols NaOH = 2.5g/molar mass NaOH.
mols HCl required = mols NaOH (from the equation).
Then mol HCl = M(HCl) x L(HCl). You have the molarity of the HCl and you have the mols of HCl from your calculation, which leaves just one unknown (the L). Convert that to mL.
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