Asked by Anonymous
Find the net torque on the wheel in the figure below about the axle through O perpendicular to the page, taking a = 11.0 cm and b = 23.0 cm. (Indicate the direction with the sign of your answer. Assume that the positive direction is counterclockwise.)
Answers
Answered by
Elena
The torque produced by the 10 N force is
τ = 10 •0.23 = 2.3 (N•m),
The torque produced by the 9 N force is
τ = 9 •0.23 = 2.07 (N•m),
The torque produced by the 12 N force is
τ = 12 •0.11 = - 1.32 (N•m)
The total torque is
τ =2.3 + 2.07 -1.32 = 3.5 (N•m).
τ = 10 •0.23 = 2.3 (N•m),
The torque produced by the 9 N force is
τ = 9 •0.23 = 2.07 (N•m),
The torque produced by the 12 N force is
τ = 12 •0.11 = - 1.32 (N•m)
The total torque is
τ =2.3 + 2.07 -1.32 = 3.5 (N•m).
Answered by
Anonymous
difficult
Answered by
Anonymous
Elena is right you all just need to change the sign to negative
Answered by
Melissa
Elena did the right calcutions, she just got wrong the signs
The torque produced by the 10 N force is
τ = 10 • 0.23 = - 2.3 (N m),
The torque produced by the 9 N force is
τ = 9 • 0.23 = - 2.07 (N m),
The torque produced by the 12 N force is
τ = 12 • 0.11 = + 1.32 (N m)
The total torque is
τ =- 2.3 - 2.07 +1.32 = - 3.05 (N m)
The torque produced by the 10 N force is
τ = 10 • 0.23 = - 2.3 (N m),
The torque produced by the 9 N force is
τ = 9 • 0.23 = - 2.07 (N m),
The torque produced by the 12 N force is
τ = 12 • 0.11 = + 1.32 (N m)
The total torque is
τ =- 2.3 - 2.07 +1.32 = - 3.05 (N m)
Answered by
Kyle V
Sup guys
Answered by
Paul Koch
Elena you need to do better
Answered by
Joseph Mother
Cmon Elena
Answered by
Mamamo
Pakopya guys, di ko magets si sir Daryl
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