Asked by John
Find the torque on the meter stick for each situation. Ignore the mass of the meter stick. At 1/2 meter there is a 1000g weight. At 1 meter on the same stick there is a 500g weight. What is the torque? Not understanding how to come up with this answer. Keep getting it wrong.
Answers
Answered by
bobpursley
Torque about what point? One end? The center?
Answered by
John
I don't understand your question, however here are other parts of the same question and the answers are correct.
All on the same 1 meter stick. Assuming g=10m/s/s:
500g weight on the right end of the stick; torque = 5 Nm.
750g weight on the right end of the stick; torque = 7.5 Nm
500g weight at the 1/2 way point on the stick; torque = 2.5 Nm.
All on the same 1 meter stick. Assuming g=10m/s/s:
500g weight on the right end of the stick; torque = 5 Nm.
750g weight on the right end of the stick; torque = 7.5 Nm
500g weight at the 1/2 way point on the stick; torque = 2.5 Nm.
Answered by
bobpursley
Ok, that is measureing torque about the free end.
So on your,
Torque=force*distance+force*distance
Torque=1kg*10N/kg*.5m + .5kg*10N/kg*1m
= 5Nm+5Nm=10Nm
Now note: 10m/s^2=10N/kg, which is easier to use in these, you are looking for force*distance
So on your,
Torque=force*distance+force*distance
Torque=1kg*10N/kg*.5m + .5kg*10N/kg*1m
= 5Nm+5Nm=10Nm
Now note: 10m/s^2=10N/kg, which is easier to use in these, you are looking for force*distance
Answered by
John
Thanks much. This is what I needed to understand.
Answered by
Anonymous
angular momentum of a system of particles
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