Asked by zarmeen
The combustion of propane is given by the following reaction:
C3H8 (g) + 5 O2 (g) ---> 3 CO2 (g) + 4 H2O (g)
If 5.00 L of propane are burned in in the presence of excess O2, how many liters of carbon dioxide will be formed?
C3H8 (g) + 5 O2 (g) ---> 3 CO2 (g) + 4 H2O (g)
If 5.00 L of propane are burned in in the presence of excess O2, how many liters of carbon dioxide will be formed?
Answers
Answered by
DrBob222
5.00L propane x (3 mols CO2/1 mol C3H8) = 5.00 x 3/1 = ?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.