Question

The combustion of propane (C3H8) in your BBQ occurs by the following unbalanced reaction:
C3H8(g) + O2(g)  CO2(g) + H2O(g) If 34.0 mL of CO2(g) is collected, what volume of H2O(g) also could be collected under the
same conditions?

Answer 1

Balance the equation.
C3H8 + 5O2 ==> 3CO2 + 4H2O

When using GAS reactions one may use volume (mL if you wish) as if volume = mols.
Therefore, 34.0 mL CO2 x (4 mols H2O/3 mols CO2) = 34 x (4/3) = ? mL H2O

Answer 2

45.3