Asked by Anonymous
The combustion of propane (C3H8) in your BBQ occurs by the following unbalanced reaction:
C3H8(g) + O2(g) CO2(g) + H2O(g) If 34.0 mL of CO2(g) is collected, what volume of H2O(g) also could be collected under the
same conditions?
C3H8(g) + O2(g) CO2(g) + H2O(g) If 34.0 mL of CO2(g) is collected, what volume of H2O(g) also could be collected under the
same conditions?
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