Asked by Anonymous
                Propane (C3H8) burns according to the following balanced equation: 
C3H8(g)+5O2(g)→3CO2(g)+4H2O(g)
Calculate ΔH∘rxn for this reaction using standard enthalpies of formation. (The standard enthalpy of formation of gaseous propane is -103.9 kJ/mol.)
            
        C3H8(g)+5O2(g)→3CO2(g)+4H2O(g)
Calculate ΔH∘rxn for this reaction using standard enthalpies of formation. (The standard enthalpy of formation of gaseous propane is -103.9 kJ/mol.)
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