Asked by Anonymous
Propane (C3H8) burns according to the following balanced equation:
C3H8(g)+5O2(g)→3CO2(g)+4H2O(g)
Calculate ΔH∘rxn for this reaction using standard enthalpies of formation. (The standard enthalpy of formation of gaseous propane is -103.9 kJ/mol.)
C3H8(g)+5O2(g)→3CO2(g)+4H2O(g)
Calculate ΔH∘rxn for this reaction using standard enthalpies of formation. (The standard enthalpy of formation of gaseous propane is -103.9 kJ/mol.)