Asked by ChemGal
The combustion of propane may be described by the chemical equation
C3H8(g)+5O2(g)⟶3CO2(g)+4H2O(g)
How many grams of O2(g) are needed to completely burn 12.3 g C3H8(g)?
C3H8(g)+5O2(g)⟶3CO2(g)+4H2O(g)
How many grams of O2(g) are needed to completely burn 12.3 g C3H8(g)?
Answers
Answered by
R_scott
the coefficients in the reaction equation are moles
5 moles of O2 are needed to burn 1 mole of C3H8
find the number of moles in 12.3 g of C3H8
5 moles of O2 are needed to burn 1 mole of C3H8
find the number of moles in 12.3 g of C3H8
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