Asked by libby
find the stationary points of the following function f(x)=x^3-3x^2-24x-7
Answers
Answered by
drwls
The stationary points are where df/dx = 0
So solve
3x^2 -6x -24 = 0
which is equivalent to
x^2 -2x - 8 = 0
(x-4)(x+2) = 0
That tells you you the two x values where the function is zero.
So solve
3x^2 -6x -24 = 0
which is equivalent to
x^2 -2x - 8 = 0
(x-4)(x+2) = 0
That tells you you the two x values where the function is zero.
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