Asked by Brain box
find the stationary points of
y=x^4/4+4x^3/3-2x^2-16x+1?
y=x^4/4+4x^3/3-2x^2-16x+1?
Answers
Answered by
oobleck
stationary points are where y'=0
y' = x^3 + 4x^2 - 4x - 16 = (x+4)(x+2)(x-2)
so, what do you think?
y' = x^3 + 4x^2 - 4x - 16 = (x+4)(x+2)(x-2)
so, what do you think?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.