Asked by Anonymous
Find stationary points:
y=(3x-1)(x-2)^2
y=(3x-1)(x-2)^2
Answers
Answered by
Reiny
Use the product rule in combination with the chain rule to find dy/dx
then set that equal to zero to solve for x
sub the x back into the original to find the points.
then set that equal to zero to solve for x
sub the x back into the original to find the points.
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