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Asked by Anonymous

Find stationary points:

y=(3x-1)(x-2)^2
15 years ago

Answers

Answered by Reiny
Use the product rule in combination with the chain rule to find dy/dx
then set that equal to zero to solve for x
sub the x back into the original to find the points.
15 years ago
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Find stationary points:

y=(3x-1)(x-2)^2

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