Asked by Melissa
A 60 kg student does 60 push ups in 40s . With each push up , the student must lift 70% of the body mass a height of 40cm off the floor. Assuming two significant digits, calculate the following
The work the student does against a force of gravity for each push up , assuming work is done only when the student pushes up
The total work done against the force of gravity in 40s
The power achieved for this period
The work the student does against a force of gravity for each push up , assuming work is done only when the student pushes up
The total work done against the force of gravity in 40s
The power achieved for this period
Answers
Answered by
Dev
(60 kg)(9.8 m/S^2) = Force in Newton
Answered by
Damon
m g * .40 = 60 * 9.8 * .7 = 412 Newtons force
distance up = .40 meters
work per push up = .40*412 = 165 Joules per push up
total work = 165 * 60 = 9878 Joules
power = work/time = 9878/40 = 247 watts
distance up = .40 meters
work per push up = .40*412 = 165 Joules per push up
total work = 165 * 60 = 9878 Joules
power = work/time = 9878/40 = 247 watts
Answered by
Anonymous
a)1.6 x 10^2
b) 9.6 x 10^3
c) 240W
b) 9.6 x 10^3
c) 240W
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