Asked by Katherine
You push an 37.4-kg box up an incline with an angle of 25 degrees to the horizontal with a force of 230-N.
1. What is the component of the crate's weight parallel to the surface?
2. What is the sum of the forces parallel to the surface?
3. What is the force due to friction?
4. What is th coefficient of friction?
1. What is the component of the crate's weight parallel to the surface?
2. What is the sum of the forces parallel to the surface?
3. What is the force due to friction?
4. What is th coefficient of friction?
Answers
Answered by
bobpursley
1. mgSinTheta
2. Pushingforce-weightdown
3. Unless you know acceleartion, it can't be solved.
pushing force-weightdown-frictionforce= mass*acceleration
3. mu*mg*CosineTheta=forceoffriction
2. Pushingforce-weightdown
3. Unless you know acceleartion, it can't be solved.
pushing force-weightdown-frictionforce= mass*acceleration
3. mu*mg*CosineTheta=forceoffriction
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.