Question
You push an 37.4-kg box up an incline with an angle of 25 degrees to the horizontal with a force of 230-N.
1. What is the component of the crate's weight parallel to the surface?
2. What is the sum of the forces parallel to the surface?
3. What is the force due to friction?
4. What is th coefficient of friction?
1. What is the component of the crate's weight parallel to the surface?
2. What is the sum of the forces parallel to the surface?
3. What is the force due to friction?
4. What is th coefficient of friction?
Answers
bobpursley
1. mgSinTheta
2. Pushingforce-weightdown
3. Unless you know acceleartion, it can't be solved.
pushing force-weightdown-frictionforce= mass*acceleration
3. mu*mg*CosineTheta=forceoffriction
2. Pushingforce-weightdown
3. Unless you know acceleartion, it can't be solved.
pushing force-weightdown-frictionforce= mass*acceleration
3. mu*mg*CosineTheta=forceoffriction