Ask a New Question

Question

Root of iota plus root of minus iota
13 years ago

Answers

Steve
I assume by iota you mean <i>i</i>, which is √-1

√i = (1+i)/√2
√-i = (1-i)/√2

add them to get 2/√2 = √2
13 years ago
Adarsh
Let root iota &root -iota = y
Now square on both side we get i - i+ 2 i^1/2 -i^1/2
= 2 [-i^2]^1/2
= 2
As y^2 = 2
Then y 2^1/2
9 years ago

Related Questions

Spuare root of 2*square root of 10 cube root of 1331 * square root of (1/4) = 5.5 correct? Find the cube root of 81: root(81, 3) Define Square root/Cube root 1. Square root/Cube root 2. Repeating decimal 3. Terminating decimal Define: Square root/Cube root Define: Repeating decimal Define: Terminating decimal Square root/Cube root definition: Repeating decimal definition: Terminating decimal definition: Simplify 17 square root 17 minus 9 square root 17 x3 with square root of 147 minus 2x square root of 27x4 (square root 22 - 10square root 21)(-9 + square root 2)
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use