Asked by Anonymous
integrate (t(root t)+t(root t))/t^2 dt
Answers
Answered by
Bosnian
[ t sqrt ( t ) + t sqrt ( t ) ] = 2 t sqrt ( t )
2 t sqrt ( t ) / t ^ 2 = 2 * sqrt ( t ) / [ sqrt ( t ) * sqrt ( t ) * t ] =
2 / sqrt ( t ) = 2 * t ^ ( - 1 / 2 )
int [ 2 * t ^ ( - 1 / 2 ) ] dt =
2 * t ^ ( - 1 / 2 + 1 ) / ( - 1 / 2 + 1 )=
2 * t ^ ( 1 / 2 ) / ( 1 / 2 ) =
2 * 2 * sqrt ( t ) = 4 sqrt ( t ) + C
2 t sqrt ( t ) / t ^ 2 = 2 * sqrt ( t ) / [ sqrt ( t ) * sqrt ( t ) * t ] =
2 / sqrt ( t ) = 2 * t ^ ( - 1 / 2 )
int [ 2 * t ^ ( - 1 / 2 ) ] dt =
2 * t ^ ( - 1 / 2 + 1 ) / ( - 1 / 2 + 1 )=
2 * t ^ ( 1 / 2 ) / ( 1 / 2 ) =
2 * 2 * sqrt ( t ) = 4 sqrt ( t ) + C
Answered by
Steve
I think you forgot the extra t in the denominator at
2 / sqrt ( t ) = 2 * t ^ ( - 1 / 2 )
Should be
2t^(-3/2)
and proceed from there...
2 / sqrt ( t ) = 2 * t ^ ( - 1 / 2 )
Should be
2t^(-3/2)
and proceed from there...
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