Asked by Jessica
Integrate: (The Sq. Root Of x-2)/x+1 dx Let u= (Sq. Root Of x-2)
Answers
Answered by
Damon
Possibly this might give you some ideas:
dx (x-2)^.5/(x+1)
u = (x-2)^.5
du = (1/2)(x-2)^-.5 dx
so
dx = 2(x-2)^.5 du
u^2 = x-2
so
x = u^2+2
then
du *2*u^2/(u^2+3)
from integral table:
int of dx x^2/(ax^2+c) =(x/a)-(c/a)int of dx/(ax^2+c)
dx (x-2)^.5/(x+1)
u = (x-2)^.5
du = (1/2)(x-2)^-.5 dx
so
dx = 2(x-2)^.5 du
u^2 = x-2
so
x = u^2+2
then
du *2*u^2/(u^2+3)
from integral table:
int of dx x^2/(ax^2+c) =(x/a)-(c/a)int of dx/(ax^2+c)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.