Asked by joe
integrate: (square root of (6x+4)) - (2x) dx
Answers
Answered by
Damon
do separately
(6x+4)^(1/2) dx
and
- 2 x dx
(2/3((1/6)(6x+4)^(3/2)
and
-x^2
so
(1/9)(6x+4)^(3/2) - x^2
(6x+4)^(1/2) dx
and
- 2 x dx
(2/3((1/6)(6x+4)^(3/2)
and
-x^2
so
(1/9)(6x+4)^(3/2) - x^2
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