Question

Hello, this is the last question from my homework that I get stuck at:

∫ (5^3/x - (x^8 + 9)^1/3 ) / 3x^2

will u, for sub. be = x^8 + 9?
Then du is = 8x^7 dx
x^7 dx = 1/8 du

from there I'm stuck.

Thank you

Answer 1

I suspect you have a typo. Go to

wolframalpha . com and type in

integral (5^3/x - (x^8 + 9)^1/3 ) / 3x^2 dx

Look at how it interprets it, and add parentheses till you get what you want.

That 5^3/x is a killer, especially if you meant 5^(3/x)!

Answer 2

I did mean 5^(3/x), sorry about that!