Answers by visitors named: Tommy

Iron

the metals are on the left side of the periodic with the exception of hydrogen (that's a nonmetal). The transition metals are the square thing in between the second column and the column where aluminum starts. the remaining are the nonmetals and the last column are the noble gases.

5x + 5 = 0 *Subtract 5 from both sides* 5x = -5 *Divide by 5 from both sides to isolate your variable x* x = -1

Thank you for your help :) By the way, i wanna ask which side i should start when i am asked to prove this boring identities and which formulae i should use. There r so many formulaes !!!! You know, i just dun have the "sense of mathematics". My friends can do this sum in 5 mins. I just cant figure how how he can do it.

Well, i tried to see the beauty in trigonometry but to me, it is just too HARD!!!!!!!! There r so many formulae in trigonometry and how to i know which one to use. After i stay in the desk for 15 mins, i just wanna throw this stupid book away. I cant gain anything even i try so hard.

What's that following ??

5. It contains more AgCl as the equilibrium position is on the left. 7. Increased because of the LeCheier's principal(I may mistyped the scientist'name ) -------------- The time is shorter but the concentration remains the same as the catalyst only speed up the reaction.

well, i think u have mistaken my question. what i meant is i cant memorize the sum-to-product formula and product to sum formula, which are Review Product to Sum Formulas 1. sin x cos y = (1/2) [ sin(x + y) + sin(x - y) ] 2. cos x sin y = (1/2) [ sin(x + y) - sin(x - y) ] 3. cos x cos y = (1/2) [ cos(x + y) + cos(x - y) ] 4. sin x sin y = (1/2) [ cos(x - y) - cos(x + y) ] Sum to Product Formulas 1. sin x + sin y = 2*sin[ (x + y) / 2 ]*cos[ (x - y) / 2 ] 2. sin x - sin y = 2*cos[ (x + y) / 2 ]*sin[ (x - y) / 2 ] 3. cos x + cos y = 2*cos[ (x + y) / 2 ]*cos[ (x - y) / 2 ] 4. cos x - cos y = 2*sin[ (x + y) / 2 ]*sin[ (x - y) / 2 ] 1. sin x + sin y = 2*sin[ (x + y) / 2 ]*cos[ (x - y) / 2 ] 2. sin x - sin y = 2*cos[ (x + y) / 2 ]*sin[ (x - y) / 2 ] 3. cos x + cos y = 2*cos[ (x + y) / 2 ]*cos[ (x - y) / 2 ] 4. cos x - cos y = 2*sin[ (x + y) / 2 ]*sin[ (x - y) / 2 ] Sorry for bothering you again :)

i am in my grade 11 and study in asia

I've tried the first one, and i found out that x=45n+11.25 or x=45-180n but i don't know if i am correct or not. The second one I just cant do it.

No one helped me ?! How poor I am ..........

I am asked to solve this equation, not to prove this identities.

I've check my answer key and the answers are 0, 270 and 360. I cant figure out how to do it. btw , are drwls and reiny teachers or professors ??

in the first part, r is any integer. in the second part, i wanna find the coefficient of x^7

actually my teacher didn't teach me anything about binomial theorem. This topic is self-studied.

It is additional maths. I learnt the binomial theorem, the (r+1) term theorem, how to expand the binomial expression using the the pascal triangle.

Thanks!

thank you

I like the shouting army sergeant for demand, but do you have another derogatory memory clue? i don't get the woman one....

Thank you all so much for your help!

You have recently found a location for our bakery and have begun implementing the first phases of your business plan. Your budget consists of an $80,000 loan from your family and a $38,250 small business loan. These loans must be repaid in full within 10 years.

Sorry: For some reason the other answer does not want to come up.

what does PI stand for?

First person who ever explained something to me that detailed thank you!

So volume of balloon 4/3*pi*r^3 *density of helium * g - ( 3.5 *9.81) ?

The answer of 999.9 N was one I already tried, and it was not correct :(

ok. I was able to get the first two but my last one is incorrect. i keep solving it to equal 2.53E-16 by making that k= 1/(2.5E10)^1.5 Not sure why this is incorrect..I inverted the K since the rxn is reversed and then used the multiplier as the exponent

oop just realized the third one isn't reversed....DOH! Thanks DrBob

Yea so you see what kind of instructor I am working with...at least I know I'm not the only one confused by her questions...

sorry, the molarity was .0010 M (moles/Liter)

5 drops : 1 drop = 0.5 mL

Satan is a round character. Satan’s character—or our perception of his character—changes significantly from Book I to his final appearance in Book X. In Book I he is a strong, imposing figure with great abilities as a leader and public statesmen, whereas by the poem’s end he slinks back to Hell in serpent form. Satan’s gradual degradation is dramatized by the sequence of different shapes he assumes. He begins the poem as a just-fallen angel of enormous stature, looks like a comet or meteor as he leaves Hell, then disguises himself as a more humble cherub, then as a cormorant, a toad, and finally a snake. His ability to reason and argue also deteriorates. In Book I, he persuades the devils to agree to his plan. In Book IV, however, he reasons to himself that the Hell he feels inside of him is reason to do more evil. When he returns to Earth again, he believes that Earth is more beautiful than Heaven, and that he may be able to live on Earth after all. Satan, removed from Heaven long enough to forget its unparalleled grandeur, is completely demented, coming to believe in his own lies. He is a picture of incessant intellectual activity without the ability to think morally. Once a powerful angel, he has become blinded to God’s grace, forever unable to reconcile his past with his eternal punishment. hopefully this helps?

yeah 1 & 3 are correct. 2 is alliteration whitch means you repeat a letter in words close together like-pretty palace painting

The text is only required for the first and fourth questions but I got them already. I don't get the rest. I think its no for 5 and small population for 6.

No you use -GMm/r to do this...

How do I graph them?

It doesn't always save time to do something in a hurry. The journalist took a job in the hotel to get facts for an article. Bob used raspberry flavor in the cod oil to mask the taste of the medicine. John bought a black cat to prove he wasn't superstitious.

Thank you

(2G/l^2)(M/sqrt(2)m)

y=-x+5

I don't get b or c at alll. What are the u's and a's? What are the exclamation points?

I don't get how you put 30% ionization into te problem. So far I have: pH = 4.76 + log[A^-]/[HAc^-]

Isn't imidazole c3h4n2 and not bnh2 though?

sorry for the drawing, apparently it didn't work when I submitted the question!

I understand now, thanks a lot steve!

*at which the ball reached, sorry for my bad grammar

Reduce both fractions to the simplest form which is 5/6...they read the same amount...

I did mean 5^(3/x), sorry about that!

thank you

Thank you both for taking your time to try this :)

the 0+ and (Pi/2)+ mean the limit is higher then and not + the fonction

Determine the simple interest rate at which will grow to in the months. Round your answer to the nearest tenth of percent

Some ideas perhaps??

Good Job, Great ALL Answer is right !

This not Dave my name is Tommy I don't even know who Dave is and I'm sorry if you think I am I don't know how to solve these . My dad would get really mad he is the president of Harvard lol so you can see I'm in a tight squeeze.

OHHHHH..... okay i understand now... Thanks!!

It's talking about its attitude in the 1920s.

The teacher said we should treat Canada as a patient here and then analyze its relationship with itself.

The teacher let us analyze Canada's relationship with itself in the 1920s. We are doing this in a psychological report and we should treat Canada here as a patient. I just don't understand what does he mean by attitude and where should I start?

All these

Can you write this paragraph in your own words, so I can understand, but don't make the paragraph too short.

240 Grams

I know his ideals,but I don't know how should I write about the reality? For example, october crisis, can you give me an idea how does october crisis affect his ideals?

Answers are POORHOUSES and FACTORYS.

so #1 is A and #2 is D?

Thank you soo much what grade are you in

A 0.600-kg ball traveling 4.00 m/s to the right collides with a 1.00-kg ball traveling 5.00 m/s to the left. After the collision, the lighter ball is traveling 7.25 m/s to the left. What is the velocity of the heavier ball after the collision?

the answer is 9.2 L and 34 lbs.

Thank you so much!I am happy to know that my answers weren't as far off as I originally thought. I have a PC with Windows 8. On Microsoft word I use the symbols to make accent marks but I'm not sure how to on my computer.

It's not 0%

thanks for your time:)

Yes, sorry I meant evaluate. But the equation is not √2/(2+√2). The equation is √2/2 + √2

E=Q Q=mct E=1/2mv^2*10 5mv^2=mct 5*2*3.99^2=0.1*450*t T=3.53. C

Is b. 9.909 correct?

thank you.

1gvf

1gvf Fudhshdyzyhxhxhhfjdjeie8e8ree

Won't it be A

I have another question? The connotations of which word in the poem help you understand the speaker's attitude toward fame? a. public b. dreary•• c. livelong d. admiring

Also can you correct me on this! Which of the following should you do during your second read of the multi-draft reading process? A. How has this work increased my knowledge of a subject, author, or genre? B. How dose the speaker feel about the topic?• C. How dose the poet's word choice create vivid images? D. What is the poem

Are those the right answers?

dan rides his bike to town every eighth day. sue walks to town every+fifth+day+on+what+day+are+they+likelyto+meet+in+town&ie=UTF-8&oe=UTF-8#safe=strict&q=dan+rides+his+bike+to+town+every+eighth+day.she+walks+to+town+every+fifth+day+on+what+day+are+they+likely+to+meet+in+town

Squash r good

51

Never mind found the answer here already

104 inch 94inch

3 sig figs

I agree

Thank you for your help!

Just tell me the answer

what are two precautions for this experiment

Oh shoot that’s a long time is their anyway to get it shorter?!

And alrighty thank you Mrs. Sue!!

If I look up what my IP is on google would that be the one you would need or is it a different one?

The one on google says it’s 207.171.254.238

The Fertile Crescent stretches about 650 miles from north to south. (It extends from the Mediterranean Sea to the Persian Gulf)

Plz answer all of them I dont think thats right

Thanks. Im assuming if i use wait(integar) it would make a wait between looping? yes?

^^ yes this is how you get to the right answer, if you were given a dif temp just plug it in and solve.

Im passing with all A's bec of this app. the kids at school have no idea what there missing out on