Asked by laura

a 5.0 g sample of ice was heated from -20.0 degrees C o 0 degrees C and remained solid. the specific heat of ice is 2.1 j/gC. How much heat did the ice absorb?
Answered by DrBob222
q = mass ice x specific heat x (Tfinal-Tinitial)
q = 5.0 x 2.1 x [0-(-20)] = ?
Answered by laura
so i just multiply everything?
Answered by DrBob222
yes
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