Asked by Monique
A 50g sample of metal was heated to 100 degrees Celsius and then dropped into a beaker containing 50g of water at 25 degrees Celsius. If the specific heat of the metal is .25 cal/g degrees Celsius, what is the final temperature of the water?
A. 27
B. 40
C. 60
D. 86
(units are degrees Celsius)
I don't know how to go about solving this. Help please?
Thank you
A. 27
B. 40
C. 60
D. 86
(units are degrees Celsius)
I don't know how to go about solving this. Help please?
Thank you
Answers
Answered by
DrBob222
heat lost by metal + heat gained by water = 0
[mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass H2O x specific heat water x (Tfinal-Tinitial)] = 0
Substitute and solve for Tfinal, the only unknown.
[mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass H2O x specific heat water x (Tfinal-Tinitial)] = 0
Substitute and solve for Tfinal, the only unknown.
Answered by
starese
Sample of gas is heated from 25c to 55c it will expand by
Answered by
vrydfvg
wecrwtvey
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