Question

A 125-g piece of metal is heated to 288 degrees celsius and dropped into 85.0 g of water at 26 degrees celsius. If the final temperature of water and metal is 58 degrees celsius, what is the specific heat of the metal?
heat lost by metal + heat gained by water = 0
[mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
Substitute the numbers and solve for the only unknown, the specific heat of the metal.
0.38J|g○C
700
9.76g
0.129 J/g C

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