Asked by Alicia

A 125-g piece of metal is heated to 288 degrees celsius and dropped into 85.0 g of water at 26 degrees celsius. If the final temperature of water and metal is 58 degrees celsius, what is the specific heat of the metal?
Answered by DrBob222
heat lost by metal + heat gained by water = 0
[mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
Substitute the numbers and solve for the only unknown, the specific heat of the metal.
Answered by Gab
0.38J|g○C
Answered by Anonymous
700
Answered by Felix
9.76g
Answered by Zoe
0.129 J/g C
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