Asked by sunny
a machine gun fires 10 bullets persecond into a target. each bullet weights 20 gm and had a speed of 1500 m per second .find the force neccessary to hold the gun in posotion?
Answers
Answered by
drwls
Average force = (momentum change)/time
= (bullet mass) x velocity x (10/ second)
= (bullet mass) x velocity x (10/ second)
Answered by
Damon
10/s * .02 kg = .2 kg/s
force = rate of change of momentum or m a
= change in momentum per second
= .2 kg/s * 1500 m/s
= 300 kg m/s^2 = 300 Newtons
force = rate of change of momentum or m a
= change in momentum per second
= .2 kg/s * 1500 m/s
= 300 kg m/s^2 = 300 Newtons
Answered by
Anonymous
300 Newton but how can solved
Answered by
Nikhil
300N
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