Asked by shri

a machine gun fires 25 g bullets at the rate of 600 bullets per minute with a speed of 200 m/s. calculate the force required to keep the gun in position.
Answered by Harsh singh
U= 0
V= 200m/s
T= 60s/600bullets = 1/10sec
M= 25g = .025 kg
Acceleration = ?
So , a = v-u/t = 200-0/1/10 = 2000 m/s^2
Force = ma = 0.025*2000 = 50 N
Answered by neeraj yadav
U= 0
V= 200m/s
T= 60s/600bullets = 1/10sec
M= 25g = .025 kg
Acceleration = ?
So , a = v-u/t = 200-0/1/10 = 2000 m/s^2
Force = ma = 0.025*2000 = 50 N

Answered by Pradhyumn
How can 200-0/1/10 be 2000......
Think...it will be 20..
Answered by Anonymous
200/1/10=200*10/1[reciprocal]. That's why 200/1/10=2000m/s^2
Answered by Anonymous
But in question,they ask what is the amount of force required to keep gun in same position so,by 1st law of Newton,the force will must be 0N.
Answered by Anonymous
How t=60s/600bullets
Answered by Unknown
How t=1/10
Answered by Anonymous
F = m.n.v
M = 25g =0.025kg
N = 600 bullets / 60 sec
= 10 bullet/ s
F = 0.025 × 10 × 200
= 50 N
Answered by Anonymous
As we know force equals to mass.acc
So we can write m.v-u/t
But here where is time in the formula of force
Answered by Helping Hand
50 NEWTON is the answer....👍
Answered by Gowri
50 N
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