a machine gun fires 25 g bullets at the rate of 600 bullets per minute with a speed of 200 m/s. calculate the force required to keep the gun in position.

U= 0

V= 200m/s
T= 60s/600bullets = 1/10sec
M= 25g = .025 kg
Acceleration = ?
So , a = v-u/t = 200-0/1/10 = 2000 m/s^2
Force = ma = 0.025*2000 = 50 N

U= 0

V= 200m/s
T= 60s/600bullets = 1/10sec
M= 25g = .025 kg
Acceleration = ?
So , a = v-u/t = 200-0/1/10 = 2000 m/s^2
Force = ma = 0.025*2000 = 50 N

How can 200-0/1/10 be 2000......

Think...it will be 20..

200/1/10=200*10/1[reciprocal]. That's why 200/1/10=2000m/s^2

But in question,they ask what is the amount of force required to keep gun in same position so,by 1st law of Newton,the force will must be 0N.

How t=60s/600bullets

How t=1/10

F = m.n.v

M = 25g =0.025kg
N = 600 bullets / 60 sec
= 10 bullet/ s
F = 0.025 × 10 × 200
= 50 N

As we know force equals to mass.acc

So we can write m.v-u/t
But here where is time in the formula of force

50 NEWTON is the answer....👍

50 N