Question
A rifle fires a(n) 5 g bullet with a muzzle
velocity of 360 m/s into a block of wood. The bullet comes to rest after it has made a(n)19 cm deep hole in the wood.A rifle fires a(n) 5 g bullet with a muzzle
velocity of 360 m/s into a block of wood. The bullet comes to rest after it has made a(n)19 cm deep hole in the wood.
velocity of 360 m/s into a block of wood. The bullet comes to rest after it has made a(n)19 cm deep hole in the wood.A rifle fires a(n) 5 g bullet with a muzzle
velocity of 360 m/s into a block of wood. The bullet comes to rest after it has made a(n)19 cm deep hole in the wood.
Answers
Anonymous
you can use the idea that the kinetic energy equals the amount of work of friction (Force of friction*d).
Use F(force of friction)= (m(v^2))/2d
...so F=(.005*(360^2))/2*.19= 1705.263 N
you use .005 because the mass was given in grams and the unit of N is kg*m/s so you have to convert 5g to .005kg and 19cm to .19m
Use F(force of friction)= (m(v^2))/2d
...so F=(.005*(360^2))/2*.19= 1705.263 N
you use .005 because the mass was given in grams and the unit of N is kg*m/s so you have to convert 5g to .005kg and 19cm to .19m