Question

A sniper fires a bullet at 120 m/s at 30° above the horizontal from the roof top of a 35 m high parking garage. If the bullet strikes the level ground beside the parking garage:

a) How long was the bullet in the air?

b) How far from the base of the parking garage did the bullet land?

c) At what angle did the bullet land?

Answers

Henry
Vo = 120m/s[30o]
Xo = 120*cos30 = 103.9 m/s.
Yo = 120*sin30 = 60 m/s.

a. Y = Yo * g*Tr = 0
Tr=-Yo/g = -60/-9.8 = 6.12 s. = Rise time.

h = ho + (Y^2-Yo^2)/2g
h = 35 + (0-(60^2))/-19.6 = 218.7 m.
Above gnd.

h = 0.5g*t^2 = 218.7
4.9t^2 = 218.7
t^2 = 44.63
Tf = 6.68 s. = Fall time.

Tr+Tf = 6.12 + 6.68 = 12.8 s. = Time in
air.

b. d = Xo*(Tr+Tf) = 103.9m/s * 12.8s =
1330 m.

c. Y^2 = Yo^2 + 2g*h
Y^2 = 0 + 19.6*218.7 = 4286.52
Y = 65.5 m/s.

Tan A = Y/Xo = 65.5/103.9 = 0.63041
A = 32.2o
Henry
TYPO: Change Y = Yo*g*Tr = 0 to
Y = Yo + g*Tr = 0
Corey Brown
Thanks Henry,

You're a good guy!
henry the best
honestly henry u is smart and loyal love ya
Aman Dixit
What is Y supposed to be?
Aman Dixit
Y^2 = Yo^2 + 2g*h

In that formula, what is Y??

I know Yo is vertical velocity, g is gravity and h is height but what is Y?
DAMN! they teaching kids about rifle basics in school?!?!?! WOW, just wow.

Related Questions