Asked by Danielle
A substance (CD) decomposes into C and D
At the temperature of the experiment, 15.0% of CD is decomposed when equilibrium is established.
a) if the initial concentration of CD is 0.200mol/L, what are the equilibrium concentrations of CD, C and D?
I got 0.17 for CD and I got 0.015 for C and D.
b) What is K for the reaction at this temperature?
I need help with b please :)
At the temperature of the experiment, 15.0% of CD is decomposed when equilibrium is established.
a) if the initial concentration of CD is 0.200mol/L, what are the equilibrium concentrations of CD, C and D?
I got 0.17 for CD and I got 0.015 for C and D.
b) What is K for the reaction at this temperature?
I need help with b please :)
Answers
Answered by
DrBob222
Thank you for posting your work. You also need help with part a.
If CD ==> C + D, then for every 1 mol CD that decomposes, you obtain 1 mol D and 1 mol C; therefore, 0.2 x 0.15 = 0.03 and the (C) = (D) = 0.03. 0.17 is correct for CD.
2.
Keq = (C)(D)/(CD) = (0.03)(o.03)/(0.17) = ?
If CD ==> C + D, then for every 1 mol CD that decomposes, you obtain 1 mol D and 1 mol C; therefore, 0.2 x 0.15 = 0.03 and the (C) = (D) = 0.03. 0.17 is correct for CD.
2.
Keq = (C)(D)/(CD) = (0.03)(o.03)/(0.17) = ?
Answered by
Danielle
Oh now it makes sense. Thank you so much DrBob222 :)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.