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Asked by Mary

Find y^1 for the relation 2 sin (x^2y)-5x^3=3y^2.
Please explain so I can work similar problems.
13 years ago

Answers

Answered by Steve
Why do you write y^1? Is that a typo for y^-1, or y inverse?

If so, forget it. You can't solve that equation explicitly for x or y.
13 years ago

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