Asked by Mary
                Find y^1 for the relation 2 sin (x^2y)-5x^3=3y^2.
Please explain so I can work similar problems.
            
        Please explain so I can work similar problems.
Answers
                    Answered by
            Steve
            
    Why do you write y^1? Is that a typo for y^-1, or y inverse?
If so, forget it. You can't solve that equation explicitly for x or y.
    
If so, forget it. You can't solve that equation explicitly for x or y.
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