Ask a New Question

Question

when sin theta+cos theta=square root of 2,find the solution of sin^3 theta+cos^3 theta
13 years ago

Answers

bobpursley
sum of two cubes..

a^3+b^3= (a+b)(a^2-ab+b^2)

= (sinT+cosT)(Sin^2T+cos^2T-sinTcosT)
= sqrt2 (1-sinTcosT)

13 years ago

Related Questions

1-2sin^2(theta/2)=2cos^2(theta/2)-1 sin theta/2cos theta/2=1/2 sine theta show the identiy and work solve 2sin^2 theta-7 sin theta= -3 for theta, where 0<theta<360 degrees r=8cos(theta)+5sin(theta), convert the polar equation into a rectangular equation and then complete... 6cos^2 theta + 5cos theta=1 Solve for theta Suppose x=4sin(theta, for theta (-pie/2, pie/2). Rewrite(sqrt16-x^2)^3/x^3 (Sorry Im not very go... if sine theta=.3416 and theta is in quadrant I what is cos theta/2? Using double angle identities. if 5sin theta + 12cos theta is equal to 13 find the value of tan theta Xsin(theta)-Ysin(theta)=rootX^2+Y^2 andcos^2(theta)/a^2+sin^2(theta)/b^2 then find correct relation Xsin(theta)-Ysin(theta)=sqrtX^2+Y^2 and cos^2(theta)/a^2+sin^2(theta)/b^2=1/X^2+Y^2 then find correc...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use