Ask a New Question

Question

sketch the region bounded by the graphs of f(y)=(y/Squareroot of(16-y^2)), g(y)=0, y=3 and find the area of the region.
13 years ago

Answers

Reiny
x = y/√(16-y^2)
as seen on Wolfram
http://www.wolframalpha.com/input/?i=x+%3D+y%2F√%2816-y%5E2%29

taking horizontal slices
Area = ∫( y/(16-y^2)^(1/2) dy from 0 to 3
= - (16-y^2)^(1/2) | from 0 to 3
= -(16-9)^(1/2) - (-16^(1/2))
= -√7 + 4
= 4-√7 = appr 1.35
13 years ago

Related Questions

Consider the region bounded by the parabola y=x^2 and the line y=16 . (a) What is the volume of t... Sketch the region bounded by the curves y = x^2, y = x^4. 1) Find the area of the region enclosed... Sketch the region bounded by the graphs of the algebraic functions & find the area of the region:... sketch the region R bounded by the graphs of the equations, and find the volume of the solid generat... Sketch the region R bounded by y=x+6, y=x^3, and 2y+x=0 then find its area. I know sketching is... Sketch the regions bounded by the following curves and find their area: y=2x^2 y=-x^3+3x Sketch the region bounded by the x-axis, the curve y = x2 + x + 1 and the lines x = 2 and x = 5. Wr... The region R bounded by the lines x=O, y= nf6, y=nfQ,, and the curve x - cos y. Consider the region R bounded by f(x) = ln x, x = e, and the x-axis. The units on the axes are in me... Consider the region bounded by the graphs of x=y^2 and x=9. Find the volume of the solid that has th...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use