Ask a New Question

Asked by Mo

The region bounded by y= 1/(x^2+2x+5), y=0, x=0, and x=1, is revolved about the x-axis. Find the volume of the resulting solid.
13 years ago

Answers

Answered by Reiny
volume
= π∫1/(x^2 + 2x + 5)^2 dx from 0 to 1

messy integration, I don't know how to do it,
Wolfram says:
http://integrals.wolfram.com/index.jsp?expr=1%2F%28x%5E2%2B2x%2B5%29%5E2&random=false
13 years ago

Related Questions

Let A be the bounded region enclosed by the graphs of f(x) = x , g(x) = x3 . Find the volume of t... Consider the region bounded by the parabola y=x^2 and the line y=16 . (a) What is the volume of t... Let R be the region bounded by y=e^x, y=2. and the y-axis. Find the volume of the solid obtained by... The region bounded by y=-x^2+14-45 and y=0 is rotated about the y-axis, find the volume. Let R be the region bounded by the curve x=9y-y^2 and the y- axis. Find the volume of the solid resu... 1. Consider the region bounded by the curves y=|x^2+x-12|, x=-5, and x=5 and the x-axis. A. Set u... The region R is bounded by the x-axis, y-axis, x = 3 and y = 1/(sqrt(x+1)) A. Find the area of r... The region R is bounded by the x-axis, x = 1, x = 3, and y = 1/x^3 A) Find the area of R B) B... Let R be the region bounded between the plane z = 1 and the cone z = 2 − p x 2 + y 2 . Describe... Let R be the region bounded by the following curves. Use the disk​ (washer) method to find the volum...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use