Asked by Mo
The region bounded by y= 1/(x^2+2x+5), y=0, x=0, and x=1, is revolved about the x-axis. Find the volume of the resulting solid.
Answers
Answered by
Reiny
volume
= π∫1/(x^2 + 2x + 5)^2 dx from 0 to 1
messy integration, I don't know how to do it,
Wolfram says:
http://integrals.wolfram.com/index.jsp?expr=1%2F%28x%5E2%2B2x%2B5%29%5E2&random=false
= π∫1/(x^2 + 2x + 5)^2 dx from 0 to 1
messy integration, I don't know how to do it,
Wolfram says:
http://integrals.wolfram.com/index.jsp?expr=1%2F%28x%5E2%2B2x%2B5%29%5E2&random=false
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