Asked by Priscilla

Two blocks are connected by a string, The smooth inclined surface makes an angle of 35 degrees with the horizontal, and the block on the incline has a mass of 5.7kg. The mass of the hanging block is m=3.2kg. Find the direction and magnitude of the hanging blocks acceleration?

Given
theta = 35 deg
m of incline = 5.7 kg
m of hanging block = 3.2 jg
a = ?

Can we use this equation
f = mgsin(theta)
Answered by Henry
W1 = mg = 5.7kg * 9.8N/kg = 55.9 N. =
Wt of block 1.

F1 = 55.9N @ 35 Deg.
Fp = 55.9*sin35 = 32 N. = Force parallel to incline.

a = Fp/m2 = 32 / 3.2 = 10 m/s^2, Up.
Answered by David
Henry is wrong... lol