Asked by stephanie
                two blocks are connected by a string. the smooth incline surface makes an angle of 42 degrees with the horizontal, andthe block on the incline has a mass of 6.7 kg. find the mass of the hanging block that will cause the system to be in equilibrium. (the pully is assumed to be ideal.)
            
            
        Answers
                    Answered by
            stephanie
            
    Let mass of hanging block be M
Since in equilibrium the hanging mass MG = Tension in the wire
Similarly along the incline Tension in the wire = 6.7 * g * sin 42 (Component of force along the incline)
So equation both the equations:
M*g = 6.7 * g * sin(42)
M = 6.7*sin(42)
So M = 6.7*sin(42)
    
Since in equilibrium the hanging mass MG = Tension in the wire
Similarly along the incline Tension in the wire = 6.7 * g * sin 42 (Component of force along the incline)
So equation both the equations:
M*g = 6.7 * g * sin(42)
M = 6.7*sin(42)
So M = 6.7*sin(42)
                    Answered by
            Amjaad
            
    Two blocks are connected by a string, as shown in the figure. The system is in equilibrium. The inclined
    
                    Answered by
            veronica
            
    6.14
    
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