Asked by Lily
How do I solve this rational exponent equation?
(2x)^1/2 = x - 4
Thanks in advance ^^
(2x)^1/2 = x - 4
Thanks in advance ^^
Answers
Answered by
Pk
Square both side first
2x)^1/2^2=(x-4)^2
2x=x^2-8x+16
subtract 2x from both sides
x^2-10x+16
now FOIL
(x-8)(x-2)
2x)^1/2^2=(x-4)^2
2x=x^2-8x+16
subtract 2x from both sides
x^2-10x+16
now FOIL
(x-8)(x-2)
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